Some courses have different handicap values for men and women. So if you're playing a match play even of a man vs. a woman, after their course handicaps are determined, which handicap values do you use, for the man or the woman? I read through the USGA manual and couldn't find this specific instance in there.

Usually what is done is you calculate the respective course handicaps for the different tees they're gonna play and set the lower course handicap = 0. e.g. if the man is a 9 chcp and the woman of the ladies tees a 15, that's a 6 shot difference. As per the 75% rule the man would have to spot the lady 4.5 = 5 shots for the 18 holes.

IMHO match plays of men vs. women should outlawed.
I had to play my first round match of our club match play championship vs. a 14year old girl. On every teeshot she drove it past me by at least 20y...WITH HER 3W!!! I was even thru 7 and a mere 1up, with 3 more holes to come where she had one stroke on me. It became clear very quickly I stood no chance... although being a 6 hcp, I do have a couple of bad holes every round, and with those she quickly was 4 up with 4 to play...go figure. Well, there's always next year...

I understand how to calculate the handicaps for each person on their respective tees. But what do you do when the handicap value for a man vs. a woman is different for each of the holes? Which holes do they get their strokes on in match play?

From the USGA Handicap Manual:

"In mixed competitions where players play their own ball and where allocations are different for men and women, the players receive strokes based on their respective stroke allocations.

In mixed foursome and selected drive match play competitions, strokes are received based on the men's allocation."

Based on this, it appears if the man has the lower handicap, the woman gets strokes based on the women's allocation.

Thanks, I missed that part.